Dibs.
Dibs.
Hopefully this post will be moot, not mute.
Hopefully this post will be moot, not mute.
What ensures some planar continuum X has pi_1(X) homeomorphic to G, with the natural quotient topology?
What ensures some planar continuum X has pi_1(X) homeomorphic to G, with the natural quotient topology?
Closed subgroups need not be compactly generated.
If A is the group of all bounded sequences of integers, so that uniformly bounded null sequences converge to 0, let B denote the subgroup with b in B iff n divides b_n.
Closed subgroups need not be compactly generated.
If A is the group of all bounded sequences of integers, so that uniformly bounded null sequences converge to 0, let B denote the subgroup with b in B iff n divides b_n.
Start with X= [0,1] x {1,2,3,....}
Now glue together (0,n) and (0,m).
The quotient space is not 1st countable, despite being locally connected and uniquely arcwise connected.
Start with X= [0,1] x {1,2,3,....}
Now glue together (0,n) and (0,m).
The quotient space is not 1st countable, despite being locally connected and uniquely arcwise connected.
"Students pay premium prices for information that AI now delivers instantly and for free. A business student can ask ChatGPT to explain supply chain optimization or generate market analysis in seconds. The traditional lecture-and-test model faces its Blockbuster moment."
The entire bottom 50% of America is worth just $4.2 trillion.
Read that back.
When 400 people control more wealth than half a country’s population, we have a very serious problem.
The entire bottom 50% of America is worth just $4.2 trillion.
Read that back.
When 400 people control more wealth than half a country’s population, we have a very serious problem.
Suppose A is an abelian group.
Suppose U is a ` not both u and -u subset', if u is in U then -u is NOT in U.
Then vU is ALSO a ` not both u and -u' subset, for each automorphism v:A-->A.
Suppose A is an abelian group.
Suppose U is a ` not both u and -u subset', if u is in U then -u is NOT in U.
Then vU is ALSO a ` not both u and -u' subset, for each automorphism v:A-->A.
47^(73)= 932 mod 1009 , we can do this quickly with a cheap calculator, via repeated doubling, since 73=64+8+1.
But BOTH chatgpt and google AI cannot stick the landing on the question:
What is 47^(73) mod 1009?
47^(73)= 932 mod 1009 , we can do this quickly with a cheap calculator, via repeated doubling, since 73=64+8+1.
But BOTH chatgpt and google AI cannot stick the landing on the question:
What is 47^(73) mod 1009?
openletter.earth/open-letter-...
2[ (10/36)(5/11) + (8/36)(4/10) +(6/36)(3/9) ) =
98.58585858....%
Don't Pass: 2[3/36]+1[1/36]+
2[ (10/36)(6/11) + (8/36)(6/10) +(6/36)(6/9) ) =
98.636363....%
2[ (10/36)(5/11) + (8/36)(4/10) +(6/36)(3/9) ) =
98.58585858....%
Don't Pass: 2[3/36]+1[1/36]+
2[ (10/36)(6/11) + (8/36)(6/10) +(6/36)(6/9) ) =
98.636363....%
www.the-reframe.com/simple-talk-2/
www.the-reframe.com/simple-talk-2/
by Eugenia Cheng
www.nytimes.com/2025/09/05/o...
(surely the ≈1k comments will be thoughtful and constructive...)
by Eugenia Cheng
www.nytimes.com/2025/09/05/o...
(surely the ≈1k comments will be thoughtful and constructive...)
Here's a must read from Scott Aaronson.
www.scottaaronson.com/papers/philo...
Here's a must read from Scott Aaronson.
www.scottaaronson.com/papers/philo...
Clay Shirky
Resonates. Heavy emphasis on idiosyncratic and improvised.
Clay Shirky
Resonates. Heavy emphasis on idiosyncratic and improvised.
You have a right to see this file.
(Published May 2023)
You have a right to see this file.
(Published May 2023)
Because sacrificing people *is* the problem.
Breaking the premise, embracing the obstacles, pursing everything.
www.the-reframe.com/there-is-no-...
Because sacrificing people *is* the problem.