A. Sum[(-1)^(n+1) sin(n)/n]
B. Sum[(-1)^(n+1) (sin(n)/n)^2]
C. Sum[(-1)^(n+1) (sin(n)/n)^3]
(via Stan Wagon)
I think @gregegansf.bsky.social will find this one particularly interesting.
A. Sum[(-1)^(n+1) sin(n)/n]
B. Sum[(-1)^(n+1) (sin(n)/n)^2]
C. Sum[(-1)^(n+1) (sin(n)/n)^3]
(via Stan Wagon)
I think @gregegansf.bsky.social will find this one particularly interesting.
New York Review of Books
London Review of Books
Times Literary Supplement
LA Review of Books
The New Yorker
Boston Review
n+1
Paris Review
New York Review of Books
London Review of Books
Times Literary Supplement
LA Review of Books
The New Yorker
Boston Review
n+1
Paris Review