So P(fire any car) = 100,000/33,930,000 = ~0.0029
There are ~1.36m EVs. 232 is the fig the Torygraph gives for # fires.
So P(fire EV car) = 232/1,360,000 = ~0.0002
So a regular car fire is >10 times more likely than an EV.
So P(fire any car) = 100,000/33,930,000 = ~0.0029
There are ~1.36m EVs. 232 is the fig the Torygraph gives for # fires.
So P(fire EV car) = 232/1,360,000 = ~0.0002
So a regular car fire is >10 times more likely than an EV.