Tamás Görbe
@tamasgorbe.bsky.social
Mathematician at Groningen
https://tamasgorbe.com/
https://tamasgorbe.com/
∫∫∫ INTEGRAL DAY ∫∫∫
The integral symbol is 350 years old! On October 29th, 1675 Leibniz has written down the first ever integral sign (see the image).
Let's celebrate integral day by sharing your favourite integral or integral related fact / content.
The integral symbol is 350 years old! On October 29th, 1675 Leibniz has written down the first ever integral sign (see the image).
Let's celebrate integral day by sharing your favourite integral or integral related fact / content.
October 28, 2025 at 12:22 PM
∫∫∫ INTEGRAL DAY ∫∫∫
The integral symbol is 350 years old! On October 29th, 1675 Leibniz has written down the first ever integral sign (see the image).
Let's celebrate integral day by sharing your favourite integral or integral related fact / content.
The integral symbol is 350 years old! On October 29th, 1675 Leibniz has written down the first ever integral sign (see the image).
Let's celebrate integral day by sharing your favourite integral or integral related fact / content.
“springs, strings, airplane wings
steel beams, light beams, and water streams
building sways, ocean waves, and sound waves...”
— Peter Lax (1926-2025)
steel beams, light beams, and water streams
building sways, ocean waves, and sound waves...”
— Peter Lax (1926-2025)
May 17, 2025 at 7:10 PM
“springs, strings, airplane wings
steel beams, light beams, and water streams
building sways, ocean waves, and sound waves...”
— Peter Lax (1926-2025)
steel beams, light beams, and water streams
building sways, ocean waves, and sound waves...”
— Peter Lax (1926-2025)
Planets ~ Springs | The Newton-Hooke Duality and Beyond tamasgorbe.wordpress.com/2025/05/09/p...
Planets ~ Springs | The Newton-Hooke Duality and Beyond
Everything’s a spring!? When I’m in a cheeky mood, I like to tease first-year physics students by telling them that for physicists everything is a spring1 or a (potentially infinite) co…
tamasgorbe.wordpress.com
May 12, 2025 at 1:46 PM
Planets ~ Springs | The Newton-Hooke Duality and Beyond tamasgorbe.wordpress.com/2025/05/09/p...
Me (15 years ago):
Definitions < Theorems
Me (now):
Definitions > Theorems
Definitions < Theorems
Me (now):
Definitions > Theorems
March 17, 2025 at 8:03 PM
Me (15 years ago):
Definitions < Theorems
Me (now):
Definitions > Theorems
Definitions < Theorems
Me (now):
Definitions > Theorems
Measuring π using a Planimeter #PiDay 2025
YouTube video by Tamás Görbe
youtu.be
March 14, 2025 at 2:11 PM
Science is prose, Mathematics is poetry.
March 13, 2025 at 8:56 AM
Science is prose, Mathematics is poetry.
The inverse trig functions arcsin and arccos as actual arc lengths
February 12, 2025 at 2:37 PM
The inverse trig functions arcsin and arccos as actual arc lengths
My favourite matrix identity
the determinant of the exponential equals the exponential of the trace
the determinant of the exponential equals the exponential of the trace
February 12, 2025 at 2:34 PM
My favourite matrix identity
the determinant of the exponential equals the exponential of the trace
the determinant of the exponential equals the exponential of the trace
Fibonacci Numbers via Matrix Multiplication
February 4, 2025 at 2:02 PM
Fibonacci Numbers via Matrix Multiplication
Gabriel's Horn is a solid you get by rotating the hyperbola y=1/x (with x>1) about the x-axis.
Having finite volume (π) and infinite(!) surface area, it leads to the apparent paradox:
"You can fill it with paint, but you cannot coat it."
Having finite volume (π) and infinite(!) surface area, it leads to the apparent paradox:
"You can fill it with paint, but you cannot coat it."
February 3, 2025 at 2:17 PM
Gabriel's Horn is a solid you get by rotating the hyperbola y=1/x (with x>1) about the x-axis.
Having finite volume (π) and infinite(!) surface area, it leads to the apparent paradox:
"You can fill it with paint, but you cannot coat it."
Having finite volume (π) and infinite(!) surface area, it leads to the apparent paradox:
"You can fill it with paint, but you cannot coat it."
Pascal's Determinant
Any square matrix cut from the top corner of Pascal's Triangle has determinant 1.
Any square matrix cut from the top corner of Pascal's Triangle has determinant 1.
January 30, 2025 at 1:55 PM
Pascal's Determinant
Any square matrix cut from the top corner of Pascal's Triangle has determinant 1.
Any square matrix cut from the top corner of Pascal's Triangle has determinant 1.
Consider the function
f(x) = 1 / ( ⌊x⌋ + 1 − {x} )
and the sequence of numbers
0, f(0), −f(0), f(f(0)), −f(f(0)), f(f(f(0))), −f(f(f(0))), ...
Congratulations, you've just listed every rational number exactly once!
f(x) = 1 / ( ⌊x⌋ + 1 − {x} )
and the sequence of numbers
0, f(0), −f(0), f(f(0)), −f(f(0)), f(f(f(0))), −f(f(f(0))), ...
Congratulations, you've just listed every rational number exactly once!
January 29, 2025 at 12:35 PM
Consider the function
f(x) = 1 / ( ⌊x⌋ + 1 − {x} )
and the sequence of numbers
0, f(0), −f(0), f(f(0)), −f(f(0)), f(f(f(0))), −f(f(f(0))), ...
Congratulations, you've just listed every rational number exactly once!
f(x) = 1 / ( ⌊x⌋ + 1 − {x} )
and the sequence of numbers
0, f(0), −f(0), f(f(0)), −f(f(0)), f(f(f(0))), −f(f(f(0))), ...
Congratulations, you've just listed every rational number exactly once!
Trigonometric Addition Formulas
− a visual proof −
sin(α+β) = sin(α)cos(β) + cos(α)sin(β)
cos(α+β) = cos(α)cos(β) – sin(α)sin(β)
− a visual proof −
sin(α+β) = sin(α)cos(β) + cos(α)sin(β)
cos(α+β) = cos(α)cos(β) – sin(α)sin(β)
January 28, 2025 at 12:31 PM
Trigonometric Addition Formulas
− a visual proof −
sin(α+β) = sin(α)cos(β) + cos(α)sin(β)
cos(α+β) = cos(α)cos(β) – sin(α)sin(β)
− a visual proof −
sin(α+β) = sin(α)cos(β) + cos(α)sin(β)
cos(α+β) = cos(α)cos(β) – sin(α)sin(β)
Everyone knows that all circles are similar. But did you know that all parabolas are similar?
The ratio of the red arc and the blue focal segment is
√2 + ln(1+√2) = 2.29558...
for every parabola.
This is the universal parabolic constant, the “π of parabolas”.
The ratio of the red arc and the blue focal segment is
√2 + ln(1+√2) = 2.29558...
for every parabola.
This is the universal parabolic constant, the “π of parabolas”.
January 27, 2025 at 11:23 AM
Everyone knows that all circles are similar. But did you know that all parabolas are similar?
The ratio of the red arc and the blue focal segment is
√2 + ln(1+√2) = 2.29558...
for every parabola.
This is the universal parabolic constant, the “π of parabolas”.
The ratio of the red arc and the blue focal segment is
√2 + ln(1+√2) = 2.29558...
for every parabola.
This is the universal parabolic constant, the “π of parabolas”.
