Sailing Lilith
@sailinglilith.bsky.social
Adventures of the satanic sailor and their demon cat Lucifur.
Great question. I have not tested range, but theoretically travelling at 2/3 hull speed (4 knots = 1.5 kW draw) then range = kWH/kW = 14.4kWH/1.5kW = 9.6 hours --> 9.6 x 4 = 38.4 nautical miles.
That said, the purpose of the auxiliary is for in and out of harbour, and not for distance.
That said, the purpose of the auxiliary is for in and out of harbour, and not for distance.
March 5, 2025 at 11:28 PM
Great question. I have not tested range, but theoretically travelling at 2/3 hull speed (4 knots = 1.5 kW draw) then range = kWH/kW = 14.4kWH/1.5kW = 9.6 hours --> 9.6 x 4 = 38.4 nautical miles.
That said, the purpose of the auxiliary is for in and out of harbour, and not for distance.
That said, the purpose of the auxiliary is for in and out of harbour, and not for distance.
Well, I pulled out the Westerbeke 27 HP motor and replaced it with a 13Kw electric motor from #Thunderstruck
Then I cut open the cockpit and removed the fuel tank. Currently I am rebuilding the cockpit.
My power comes from 3x 48V 100Ah #Lynac lithium iron phosphate batteries.
Then I cut open the cockpit and removed the fuel tank. Currently I am rebuilding the cockpit.
My power comes from 3x 48V 100Ah #Lynac lithium iron phosphate batteries.
March 5, 2025 at 9:57 PM
Well, I pulled out the Westerbeke 27 HP motor and replaced it with a 13Kw electric motor from #Thunderstruck
Then I cut open the cockpit and removed the fuel tank. Currently I am rebuilding the cockpit.
My power comes from 3x 48V 100Ah #Lynac lithium iron phosphate batteries.
Then I cut open the cockpit and removed the fuel tank. Currently I am rebuilding the cockpit.
My power comes from 3x 48V 100Ah #Lynac lithium iron phosphate batteries.