not-a-beetle.bsky.social
@not-a-beetle.bsky.social
2^((2/d - 1)) * ∑[ (1 / (2^d)) * (Δx)^d ] (d = 1 to ∞) ∝ A^(d-1)
January 26, 2025 at 11:37 PM
D = (d + 1) / (d - 1) + (1 / (d - 1)) * ∑[ (d - 1)^n / (d - 1)^n ] (n = 1 to ∞)

I = (A / 4G) * (1 / (4π)) * ∑[ (1 / (4π)) * (Δx)^d ] (d = 1 to ∞)

N = (2^D) / (2^d) * ∑[ (1 / (2^d)) * (Δx)^d ] (d = 1 to ∞)

t = (T / (2π)) * ∑[ (1 / (2π)) * sin(2π * t / T)^n ] (n = 1 to ∞)
January 26, 2025 at 11:33 PM