then you could check against "0","1",etc, but it's not an elegant solution & I don't wanna confuse you, since I don't know your course's intention & socmed isn't the best format for teaching =/ just don't be too hard on yourself! Thinking like a dev takes years & soon you'll encounter stackoverflow~

there are many ways to check matches, depending which datastructures you're familiar with. Maybe a "i in {0,1,2,3,4,5,6,7,8,9}" would already do it, but you could also do it more verbose by checking each digit per individual if where you either print it on true or advance to the next on false o:

Python got a lot of handy methods! Doubt you gonna learn all of them in a course, but there was probably also the option of going char by char to check if it matches (0-9), depending how tricky your input (containing floats/hex) or robust your solution is supposed to be~ Also see isdigit() :>

Made me realize I've also shared way too few non-English tracks in this Bsky thread so far (Which are also not Japanese or German for once)... So have some Norwegian pop for a change o: #evumusic

Made me realize I've also shared way too few non-English tracks in this Bsky thread so far (Which are also not Japanese or German for once)... So have some Norwegian pop for a change o: #evumusic