\\[ x = \sum_{n\geq 0} C_n\\]
where \\(C_n = \frac{1}{1+n} \binom{2n}{n}\\) is the \\(n\\)th […]
[Original post on mathstodon.xyz]
\\[ x = \sum_{n\geq 0} C_n\\]
where \\(C_n = \frac{1}{1+n} \binom{2n}{n}\\) is the \\(n\\)th […]
[Original post on mathstodon.xyz]
interestingengineering.com/science/math...
m.winfuture.de/news/150903
www.tandfonline.com/doi/epdf/10....
www.tandfonline.com/doi/full/10....
www.tandfonline.com/doi/full/10....
Of course, it doesn't do that at all, but it *is* very interesting and extraordinarily good on citing previous work. 🧵
www.tandfonline.com/doi/full/10....
Of course, it doesn't do that at all, but it *is* very interesting and extraordinarily good on citing previous work. 🧵
www.tandfonline.com/doi/full/10....