Ioana
@contrails.uk
IRL an autistic mute.
In my spare time I go birdwatching, take photos and paint, results of which are available on my other a/c @ioana-logafatu.bsky.social
I do a bit of programming too; check out the contrail prediction plugin for windy.com 🤓
In my spare time I go birdwatching, take photos and paint, results of which are available on my other a/c @ioana-logafatu.bsky.social
I do a bit of programming too; check out the contrail prediction plugin for windy.com 🤓
‘Over the target’ is my favourite conspiracy phrase. In reality, the weirder you get, the bigger the crowd that gathers to watch. 😁
September 4, 2025 at 4:22 PM
‘Over the target’ is my favourite conspiracy phrase. In reality, the weirder you get, the bigger the crowd that gathers to watch. 😁
Elephant = 1, Cat = 0 ?
Did the elephant sit on the cat?
Did the elephant sit on the cat?
July 29, 2025 at 9:00 AM
Elephant = 1, Cat = 0 ?
Did the elephant sit on the cat?
Did the elephant sit on the cat?
He used an arbitrary figure of 5 for the length of the side, which is perfectly valid as we want the angles.
That makes the cosine rule easier. I was trying to juggle around with X, Y and theta 🙄
That makes the cosine rule easier. I was trying to juggle around with X, Y and theta 🙄
July 21, 2025 at 12:36 PM
He used an arbitrary figure of 5 for the length of the side, which is perfectly valid as we want the angles.
That makes the cosine rule easier. I was trying to juggle around with X, Y and theta 🙄
That makes the cosine rule easier. I was trying to juggle around with X, Y and theta 🙄
I spent a long time playing around with sine and cosine rules, which always amazes me that they still lurk in my memory since the 70’s. I would rather use that bit of memory to recall why I went into the kitchen. 😬
July 21, 2025 at 6:36 AM
I spent a long time playing around with sine and cosine rules, which always amazes me that they still lurk in my memory since the 70’s. I would rather use that bit of memory to recall why I went into the kitchen. 😬
30 🤯
I admit I got a pointer to solve it by extending the isosceles triangles. It was quite satisfying getting to the end. 🤓
I admit I got a pointer to solve it by extending the isosceles triangles. It was quite satisfying getting to the end. 🤓
July 20, 2025 at 10:26 PM
30 🤯
I admit I got a pointer to solve it by extending the isosceles triangles. It was quite satisfying getting to the end. 🤓
I admit I got a pointer to solve it by extending the isosceles triangles. It was quite satisfying getting to the end. 🤓
Having let this bother me all night, I came up with B on the basis that the true answer is +/- 5 but as we can see which root led to the interim 25, we can eliminate the +5 answer.
July 19, 2025 at 9:05 AM
Having let this bother me all night, I came up with B on the basis that the true answer is +/- 5 but as we can see which root led to the interim 25, we can eliminate the +5 answer.
Do I need to resort to my "you need to refer to the system the notation is attempting to model to resolve the ambiguity" answer?
July 18, 2025 at 12:04 PM
Do I need to resort to my "you need to refer to the system the notation is attempting to model to resolve the ambiguity" answer?
I had to spice it up a bit with parallel lines and alternate interior angles. 😁
July 15, 2025 at 9:33 AM
I had to spice it up a bit with parallel lines and alternate interior angles. 😁
Nothing is more dangerous than dehydrated dihydrogen monoxide 😬
July 14, 2025 at 4:31 PM
Nothing is more dangerous than dehydrated dihydrogen monoxide 😬
Being teachers pet 🐕 I worked out an alternative way. The given dimensions will be in a fixed relationship.
Y = 2X - L (L is the side length)
I worked that out by looking at the extremes and the midway point.
Then it is a simple case of using the given figures to give us a side length of 6.9
Y = 2X - L (L is the side length)
I worked that out by looking at the extremes and the midway point.
Then it is a simple case of using the given figures to give us a side length of 6.9
July 14, 2025 at 1:45 PM
Being teachers pet 🐕 I worked out an alternative way. The given dimensions will be in a fixed relationship.
Y = 2X - L (L is the side length)
I worked that out by looking at the extremes and the midway point.
Then it is a simple case of using the given figures to give us a side length of 6.9
Y = 2X - L (L is the side length)
I worked that out by looking at the extremes and the midway point.
Then it is a simple case of using the given figures to give us a side length of 6.9
Note: If AE gets smaller, so does BF. That demonstrates it is not a simple case of adding them.
July 14, 2025 at 1:39 PM
Note: If AE gets smaller, so does BF. That demonstrates it is not a simple case of adding them.
The corrected version - 20.616
July 14, 2025 at 9:14 AM
The corrected version - 20.616
I like to retract my answer having just realised my calculator was set to radians 🙄
And having just realised I should know what sin 30 was 😬
And having just realised I should know what sin 30 was 😬
July 14, 2025 at 9:09 AM
I like to retract my answer having just realised my calculator was set to radians 🙄
And having just realised I should know what sin 30 was 😬
And having just realised I should know what sin 30 was 😬
and Stonehenge isn't a henge. 😬
July 9, 2025 at 8:34 AM
and Stonehenge isn't a henge. 😬
I made the list for pointing out Bob Geldof was Irish.
July 8, 2025 at 10:05 AM
I made the list for pointing out Bob Geldof was Irish.