anyway, i'm some dude with adhd and a furry.
For reference, a standard twin-size bed is 3'4 x 6'3.
And that supports the size of an adult male.
IN CONCLUSION: You can comfortably sleep on Puppy's tail.
For reference, a standard twin-size bed is 3'4 x 6'3.
And that supports the size of an adult male.
IN CONCLUSION: You can comfortably sleep on Puppy's tail.
www.desmos.com/calculator/m...
Anyway, after that misery, we get to a number of about 566 pixels for the length of their tail from base to tip.
566 pixels is 95 inches, which is a staggering 7 FOOT 11 INCHES.
www.desmos.com/calculator/m...
Anyway, after that misery, we get to a number of about 566 pixels for the length of their tail from base to tip.
566 pixels is 95 inches, which is a staggering 7 FOOT 11 INCHES.
That's not easily discernable with the pythagorean theorem though, because it's a curve.
The length of a bezier curve is basically impossible to compute numerically, so we need to approximate it with straight lines.
That's not easily discernable with the pythagorean theorem though, because it's a curve.
The length of a bezier curve is basically impossible to compute numerically, so we need to approximate it with straight lines.
To determine surface area, we will need the width and height.
Getting the width is easy, it's about 246 pixels, which is 41 inches, which is an impressive 3'5!
However, getting the height is what's going to tear us down.
To determine surface area, we will need the width and height.
Getting the width is easy, it's about 246 pixels, which is 41 inches, which is an impressive 3'5!
However, getting the height is what's going to tear us down.
According to an official TikTok post, puppy is 5'4.
5'4 in inches is 64
64 inches / 383 pixels = 0.167 inches per pixel
In other words, any measurement of puppy can be determined by multiplying the pixel length by 0.167
According to an official TikTok post, puppy is 5'4.
5'4 in inches is 64
64 inches / 383 pixels = 0.167 inches per pixel
In other words, any measurement of puppy can be determined by multiplying the pixel length by 0.167