Andrej Bauer
@andrejbauer.mathstodon.xyz.ap.brid.gy
Professor of computational mathematics at University of Ljubljana, Slovenia.
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[bridged from https://mathstodon.xyz/@andrejbauer on the fediverse by https://fed.brid.gy/ ]
A while ago I received a phone call from a man who lives in a small Slovenian town. He claimed to have squared the circle, finally after 10 years of efforts. He wanted to come to talk to me about it in Ljubljana. I asked that he first send me his construction […]
[Original post on mathstodon.xyz]
[Original post on mathstodon.xyz]
April 13, 2025 at 11:46 PM
A while ago I received a phone call from a man who lives in a small Slovenian town. He claimed to have squared the circle, finally after 10 years of efforts. He wanted to come to talk to me about it in Ljubljana. I asked that he first send me his construction […]
[Original post on mathstodon.xyz]
[Original post on mathstodon.xyz]
It's giving me ideas for very interesting exam questions in category theory that would ask the students to appraise a ChatGPT answer and either confirm it to be correct, or spot the error.
February 26, 2025 at 9:17 AM
It's giving me ideas for very interesting exam questions in category theory that would ask the students to appraise a ChatGPT answer and either confirm it to be correct, or spot the error.
Daily reminder on how good ChatGPT is. I asked it to show me the diagrams for 𝑓 : 𝑇𝐴 → 𝐴 being an algebra for the monad 𝑇.
February 26, 2025 at 9:09 AM
Daily reminder on how good ChatGPT is. I asked it to show me the diagrams for 𝑓 : 𝑇𝐴 → 𝐴 being an algebra for the monad 𝑇.
TIL I made the types.pl logo.
January 31, 2025 at 9:31 PM
TIL I made the types.pl logo.
I can never remember the formula for the closure operator 𝑗 : 𝖯𝗋𝗈𝗉 → 𝖯𝗋𝗈𝗉 forcing a predicate 𝑃 : 𝐴 → 𝖯𝗋𝗈𝗉 to be true. It is this
\\[j(q) = \forall r .\, (q \Rightarrow r) \Rightarrow (\forall x \in A.\, ((P\,x \Rightarrow r) \Rightarrow r) […]
[Original post on mathstodon.xyz]
\\[j(q) = \forall r .\, (q \Rightarrow r) \Rightarrow (\forall x \in A.\, ((P\,x \Rightarrow r) \Rightarrow r) […]
[Original post on mathstodon.xyz]
December 22, 2024 at 9:35 AM
I can never remember the formula for the closure operator 𝑗 : 𝖯𝗋𝗈𝗉 → 𝖯𝗋𝗈𝗉 forcing a predicate 𝑃 : 𝐴 → 𝖯𝗋𝗈𝗉 to be true. It is this
\\[j(q) = \forall r .\, (q \Rightarrow r) \Rightarrow (\forall x \in A.\, ((P\,x \Rightarrow r) \Rightarrow r) […]
[Original post on mathstodon.xyz]
\\[j(q) = \forall r .\, (q \Rightarrow r) \Rightarrow (\forall x \in A.\, ((P\,x \Rightarrow r) \Rightarrow r) […]
[Original post on mathstodon.xyz]