If I remove a8 (upper right) and say… e1 (fifth right in bottom row), I can tile that. In fact, if I remove two squares from anywhere (even the interior) completely at random, the odds I can tile the leftover is pretty much ½. Proving that is quite a bit more difficult.
June 13, 2024 at 1:59 AM
If I remove a8 (upper right) and say… e1 (fifth right in bottom row), I can tile that. In fact, if I remove two squares from anywhere (even the interior) completely at random, the odds I can tile the leftover is pretty much ½. Proving that is quite a bit more difficult.
That’s not entirely true: for example, say you remove the upper left and upper right corners. There are still two odd rows (columns). But you can tile that one. By way of learning, try and figure out what’s different between those two cases.
June 12, 2024 at 2:06 AM
That’s not entirely true: for example, say you remove the upper left and upper right corners. There are still two odd rows (columns). But you can tile that one. By way of learning, try and figure out what’s different between those two cases.