I believe the smallest polyhedron for which this is possible is a cuboctahedron with each square face cut into two triangles.
I believe the smallest polyhedron for which this is possible is a cuboctahedron with each square face cut into two triangles.
According to the website it's not published until tomorrow, so I don't know how I have it already. I hit the button labeled "preorder" and they sent it to me
According to the website it's not published until tomorrow, so I don't know how I have it already. I hit the button labeled "preorder" and they sent it to me
The table shows the value of
Integral_{x=0..pi} [sin(x) x^n (Pi-x)^n / n!] dx
for various values of n. For n=7, the exact value is
-112Pi^6 + 50400Pi^4 - 3991680Pi^2 + 34594560
and the approximate value is
0.102692917728.
For n=14, the approximate value is
0.000002476917.
The table shows the value of
Integral_{x=0..pi} [sin(x) x^n (Pi-x)^n / n!] dx
for various values of n. For n=7, the exact value is
-112Pi^6 + 50400Pi^4 - 3991680Pi^2 + 34594560
and the approximate value is
0.102692917728.
For n=14, the approximate value is
0.000002476917.
c^(aleph0) = (2^aleph0)^aleph0
= 2^(aleph0xaleph0)
= 2^(aleph0) = c
c^(aleph0) = (2^aleph0)^aleph0
= 2^(aleph0xaleph0)
= 2^(aleph0) = c
I just noticed the pun and ran with it
I just noticed the pun and ran with it