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@christophheilig.bsky.social @noester.bsky.social @felwert.fedihum.org.ap.brid.gy @ixtheo.bsky.social
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@christophheilig.bsky.social @noester.bsky.social @felwert.fedihum.org.ap.brid.gy @ixtheo.bsky.social
github.com/CrispStrobe/...
#Classics#AncientGreek #NewTestamentStudies
2/
github.com/CrispStrobe/...
#Classics#AncientGreek #NewTestamentStudies
2/
x^2−y^2=27
(x−y)(x+y)=27
(x−y) and (x+y) must be pos. integers, thus dividends of 27
pos. div. of 27 are 1,3,9,27, or in pairs, (1,27), (3,9)
(as we look for largest, we ignore neg.)
so either: x-y=1 & x+y=27
or: x-y=3 & x+y=9
insert (y=x-1; x+(x-1)=27; 2x-1=27...), so either x=14 or x=6
x^2−y^2=27
(x−y)(x+y)=27
(x−y) and (x+y) must be pos. integers, thus dividends of 27
pos. div. of 27 are 1,3,9,27, or in pairs, (1,27), (3,9)
(as we look for largest, we ignore neg.)
so either: x-y=1 & x+y=27
or: x-y=3 & x+y=9
insert (y=x-1; x+(x-1)=27; 2x-1=27...), so either x=14 or x=6
consider
2x = (x - y) + (x + y)
for the dividends of 27
consider
2x = (x - y) + (x + y)
for the dividends of 27
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